2y^2+8=4y

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Solution for 2y^2+8=4y equation:


Simplifying
2y2 + 8 = 4y

Reorder the terms:
8 + 2y2 = 4y

Solving
8 + 2y2 = 4y

Solving for variable 'y'.

Reorder the terms:
8 + -4y + 2y2 = 4y + -4y

Combine like terms: 4y + -4y = 0
8 + -4y + 2y2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(4 + -2y + y2) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(4 + -2y + y2)' equal to zero and attempt to solve: Simplifying 4 + -2y + y2 = 0 Solving 4 + -2y + y2 = 0 Begin completing the square. Move the constant term to the right: Add '-4' to each side of the equation. 4 + -2y + -4 + y2 = 0 + -4 Reorder the terms: 4 + -4 + -2y + y2 = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -2y + y2 = 0 + -4 -2y + y2 = 0 + -4 Combine like terms: 0 + -4 = -4 -2y + y2 = -4 The y term is -2y. Take half its coefficient (-1). Square it (1) and add it to both sides. Add '1' to each side of the equation. -2y + 1 + y2 = -4 + 1 Reorder the terms: 1 + -2y + y2 = -4 + 1 Combine like terms: -4 + 1 = -3 1 + -2y + y2 = -3 Factor a perfect square on the left side: (y + -1)(y + -1) = -3 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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